The area of a square is given by 9x2 + 54xy + 81y. Find the side of the square.
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Question : The area of a square is given by 9x² + 54xy + 81y. Find the side of the square.
Solution : Area of the Square =
9x² + 54xy + 81y
we know that Area of square is =
side × side
By simplifying we get = 9x² + 54xy + 81y
= (3)x² + 54xy + 81y
= (3)x² + 6x × 9y × 2/2 + (9)x²
= (3x + 9y)² ( a+b² = a² + b² + 2ab )
Therefore, side of the square =
(3x + 9y)²
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