Question

The area of a square is increasing at the rate
of 0.5 cm/sec. Find the rate of increase of it's
perimeter when the side of the square is 10 cm
(2 marks)
long.​

Answer 1

$\texttt{If x cm. is the side of square and p cm is the perimeter}$

$p = 4x \\ \\ \frac{dp}{dt} = 4 \frac{dx}{dt} \\ \\ = 4 \times 0.5 \\ \\ = 2$

$\texttt{The perimeter is increasing at the rate of 2cm/sec}$

Answer 2

Answer:

refer the attachment...