Question

the area of a square whose perimeter is 32cm is​

Answer 1

Explanation:

Area of a square= side^2

Perimeter=side*4

32=side*4

32/4=side

side=8cm

Area=side^2

Area=8^2

Area=8×8

Area=64cm

Answer 2

$\bf{\underline{\underline \green{Solution:-}}}$

$\frak\red{AnswEr}\begin{cases}\sf\blue{\underline{The \:area\:of\: the\:square = \: 64Cm^2}}\end{cases}$

$\frak\red{Given}\begin{cases}\sf\green{\underline{Perimeter\:of\: the\:square = 32\:Cm}}\end{cases}$

$\frak\red{Need\:To\:Find}\begin{cases}\sf\blue{\underline{The \:area\:of\: the\:square = \: ?}}\end{cases}$

$\bf{\underline{\underline \green{Explanation:-}}}$

$\underline\mathtt \orange{Formula\:used\:here:-}$

$\bigstar \: \boxed{ \sf \: Perimeter \:of \:square = 4\times Side }$

$\underline\mathtt \orange{Putting\:the\: values:-}$

$\longrightarrow \sf {32 = 4 \times Side}$

$\longrightarrow \sf{Side = \dfrac{\cancel{32}}{\cancel{4}}}$

$\longrightarrow \sf {Side = 8\:cm}$

$\underline\mathtt \orange{Hence:}$

• $\small\orange{\underline {\boxed{\sf\green{ Side = 8\:Cm} }}}$

$\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}$

$\underline\mathtt \orange{Now,Formula\:used\:here:-}$

$\bigstar \: \boxed{ \sf \: Area \: of \:square = Side \times Side }$

$\underline\mathtt\orange{Putting\:the\: values:-}$

$\longrightarrow \sf {Area \: of \:the \: square = 8\times 8 }$

$\longrightarrow \sf {Area \:of\: the \: square = 64\:cm^2 }$

$\underline\mathtt \orange{Hence:}$

• $\small\orange{\underline {\boxed{\sf\green{ Area\: of \: the \: square = 64\:cm^2} }}}$

$\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}$