Question

The area of a square with side (11a -8b) units is *

1 point

I don't know the answer

None of the above

121a² + 64b²

121a² - 64b²

121p² + 64b² - 176ab

​

Answer 1

$Given \: side \:of \:a \: square = (11a - 8b) \:units$

$\red{ Area \: of \: the \: Square }\green{= (side)^{2}}$

$= (11a-8b)^{2}$

$= (11a)^{2} + (8b)^{2} - 2 \times 11a \times 8b$

/* By Algebraic Identity */

$\boxed{\orange { (x-y)^{2} = x^{2} +y^{2}-2xy }}$

$= 121a^{2} + 64b^{2} - 176ab$

Therefore.,

$\red{ Area \: of \: the \: Square }$

$\green {= 121a^{2} + 64b^{2} - 176ab}$

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