Question

find the derivative of (cosx)^(sinx) wrt (sinx)^(cosx)​

Answer 1

Answer:

(sinx^sinx/cosx^cosx)cotx

Step-by-step explanation:

u=cosx^sinx

v=sinx^cosx

du/dv

=(du/dt)(dt/dv)

du/dt=-(sinx^sinx)*(cosx)

dv/dt=-(cosx^cosx)*(sinx)

deviding both, we get

du/dv=(sinx^sinx/cosx^cosx)cotx