Question

The area of a squared shape room is 144m^2.Find the perimeter of the room,also find the cost of chips flooring of the room at the rate of Rs.25 per m^2.​

Answer 1

Answer is in the attachement!

Answer 2

Answer:

$The \: area \: of \: a \: squared \: shape \: room \: is \: = 144 {m}^{2}$

$perimeter \: of \: the \: room \: = (4 \times side)$

$4 \times 12 = 48m$

$cost \: of \: chips \: flooring \: of \: the \: room \: at the \: rate \: of Rs.25 per {m}^{2} .$

$The \: area \: of \: a \: squared \: shap \: room \: is 144 {m}^{2}$

$for \: 144 {m}^{2} \: the \: cost \: of \: chip \: flooring \: = 25 \times 144 = 3600$