Question

the area of a trapezium field is 480m^2, the distance between two parallel sides is 15m and one of the parallel side is 20m. find the length of the other parallel side?

Answer 1

Answer:

area of trapezium =480m^2

distance (height)=15m

one of the parallel side =20m

let the length of the other parallel side be x

We know that the area of trapezium =1/2 ×(sum of 2 parallel side)× height

so ,ATQ

1/2 (x+20)×15=480

=x/2+1/2×20×15=480

=x/2+10×15=480

= 15x/2+150=480

= 15x/2=480-150

= 15x/2=330

=x=330×2/5

x=44

so the length of the other parallel side is 44m

Answer 2

Given:

◕ Area of trapezium shaped shaped field = 480 m²

◕ Distance between two parallel lines i.e., Height = 15 m

◕ One of the parallel side = 20 m

$\blue{\huge{\underline{\underline{ \rm{To \: Find: }}}}} </p><p></p><p>$

◉ The other parallel side.

$\red{\large{\underline{\underline{ \rm{Solution: }}}}} </p><p></p><p>$

Let the other parallel side be x.

We know, the area of the trapezium is given by:

Formula for Area of a trapezium:

$\green{ \underline{ \boxed{ \rm{Area = \frac{1}{2} \times (sum \: of \: parallel \: sides) \times height}}}} </p><p></p><p> </p><p>$

$</p><p> 480 = \frac{1}{2} \times (20 + x) \times 15$

$480 \times 20 = (20 + x) \times 15</p><p>$

$960 = (20 + x) \times 15 \\ 960=(20+x)×15 \\ </p><p></p><p>\frac{960}{15} = 20 + x </p><p>15 \\ </p><p>$

$64 =20+x$

We have,

$64 = 20 + x \: \\ </p><p></p><p>x = 64 - 20 \\ </p><p>$

$x = \rm44 \: cm$

∴ The other parallel side =

$\green{ \underline{ \boxed{ \rm{44 \: cm}}}} </p><p></p><p>$

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