Math, asked by devar58614, 1 year ago

The area of a trapezium is 1,586 cm2 and sum of parallel sides is 122 cm. Find the
distance between two parallel sides.

Answers

Answered by soham8580

Step-by-step explanation:

area = 1/2 × sum of parallel sides ×

distance b/w them

1586= 1/2 × 112 × x

x = 1526×2/112

= 109/4

= 27.25 cm

Answered by Battleangel

$<body bgcolor="yellow"$

$\red{area \: of \: trapezium \: = \frac{1}{2} \times (a + b) \times h}$

$\blue{1586 {cm}^{2} = \frac{1}{2} \times122cm \times h }$

$\purple{1586 {cm}^{2} = \frac{122cm}{2} \times h }$

$\pink{ \frac{1586{cm}^{2} \times 2}{122 \: cm} = h }$

$\green {\dfrac{3172 \cancel{{cm}^{2}}}{122 \cancel {cm}} = h}$

$\blue{ \cancel \frac{3172cm}{122} = h}$

$\implies \: 26cm = h$

$hence \: the \: distance \: between \: the \: parallel \\ sides = 26 \: cm \:$

$<marquee scrollamount=1200>hope this helps you xD ✌❤</marquee>$

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