the area of a trapezium is 105 sq. cm and height = 7 cm . if one side is longer than other by 6 cm find the two parallel sides
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using
area of trapezium= 1/2 × sum of parallelsides × height
given area of trap.= 105cm
and height=7cm
one side is loger 6 cm than other
let the one side be x
then other be 6+x
then use formula
105=1/2(x+6+x)×7
210/7=2x+6
30-6=2x
24=2x
x=12
so first side is 12
and other 12+6=18
area of trapezium= 1/2 × sum of parallelsides × height
given area of trap.= 105cm
and height=7cm
one side is loger 6 cm than other
let the one side be x
then other be 6+x
then use formula
105=1/2(x+6+x)×7
210/7=2x+6
30-6=2x
24=2x
x=12
so first side is 12
and other 12+6=18
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