The area of a trapezium is 120cm2
Answers
that Area Of A Trapezium Is 120 Cm Sqr And The Distance Between The Parallel Side
Is 8cm . Now We Need To Find length of the parallel side if their differences is 6cm.
\textbf{Solution}Solution ......
Now in Question it's given that ..
height \: (h) \: = \: 8cm \: \: ( \: height \: is \: distance \: between \: parallel \: lines \: )height(h)=8cm(heightisdistancebetweenparallellines)
Now Parallel Lines Electric Greater Line be = X
So According To Question It's Said That There Difference Is = 6cm
So The length of smaller line would be = X - 6
Now we know that area of a Trapezium is
\frac{1}{2} \times (a + b) \: \times h \: (where \: a \: and \: b \: are \: \: length \: of \: parallel \: lines \: )
2
1
×(a+b)×h(whereaandbarelengthofparallellines)
\: and \: h \: is \: height \:andhisheight
Therefore Now Putting Values Of a ,b And b As X , X - 6 , & 8cm Respectively...
That is ➡️
\frac{1}{2} \times( (x) + (x - 6)) \times 8
2
1
×((x)+(x−6))×8
That is ➡️
\frac{1}{2} ( \: 2x - 6) \times 8
2
1
(2x−6)×8
Now taking. 2 common from 2x-6 we have
\frac{1}{2} 2(x - 3) \times 8
2
1
2(x−3)×8
Now cancelling 1/2 and 2 we have ....
(x - 3) \times 8(x−3)×8
But In Question It's Given That Area Of Trapezium = 120 Cm Sqr
So we have ..
(x - 3) \times 8 = 120 {cm}^{2}(x−3)×8=120cm
2
That is ...
(x - 3) = \frac{120}{8} \: ( \: taking \: 8 \: to \: rhs)(x−3)=
8
120
(taking8torhs)
This is equal to ....
x - 3 = 15cmx−3=15cm
So we have ....
x = 18cmx=18cm
Hence the length of greater parallel line = X = 18cm
and
length of smaller parallel line = X-6 = 18-6 = 12cm
\textbf{Therefore required answer is ...}Therefore required answer is ...
18cm and 16 cm .
hope \: its \: help \: fullhopeitshelpfull
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Thought made by Me ....
Step-by-step explanation:
Now in Question it's given that ..
Now Parallel Lines Electric Greater Line be = X
So According To Question It's Said That There Difference Is = 6cm
So The length of smaller line would be = X - 6
Now we know that area of a Trapezium is
Therefore Now Putting Values Of a ,b And b As X , X - 6 , & 8cm Respectively...
That is ➡️
That is ➡️
Now taking. 2 common from 2x-6 we have
Now cancelling 1/2 and 2 we have ....
But In Question It's Given That Area Of Trapezium = 120 Cm Sqr
So we have ..
$$$
That is ...
This is equal to ....
So we have ....
Hence the length of greater parallel line = X = 18cm
and
length of smaller parallel line = X-6 = 18-6 = 12cm
18cm and 16 cm .
