Question

The area of a trapezium is 1440 cm2. If the lengths of its parallel sides are 54.6 cm and 35.4 cm, find the distance between them

Answer 1

Answer:

32 cm

Step-by-step explanation:

Area of trapezium = 1/2×hight (sum of the length of the parallel sides.)

1440=1/2×hight(54.6+35.4)

1440=1/2×hight(90)

1440=hight×45

1440/45=hight

32cm=hight

Distance between the parallel lines is 32cm.

Answer 2

Given:

• The area of a trapezium = 1440 $cm^2$
• The lengths of its parallel sides = 54.6 cm and 35.4 cm

To Find:

• The distance between the parallel sides.

Solution:

Let 'a' and 'b' be the two parallel sides.

a = 54.6 cm and b = 35.4 cm

The area of a trapezium is given by,

a = $\frac{1}{2}*h*(a+b)$ → (equation 1)

Where, 'h' is the distance between the parallel sides of the trapezium, 'a' and 'b' are the lengths of the parallel sides of the trapezium.

On substituting the values from the given data in equation 1 we get,

⇒1440 = $\frac{1}{2}$×h×(54.6+35.4)

⇒1440 = $\frac{1}{2}$ ×h×90 = (90/2)×h

⇒ 1440 = 45h  ( rearranging the equation such that we get the 'h' value)

⇒ h = 1440/45 = 32 cm

∴ The distance between the parallel sides = 32 cm.