Question

.The area of a trapezium is 15122 . If the ratio of the parallel sides is 9:5 and the distance between them is 24 cm. Find the length of the parallel sides.​

Answer 1

Answer:

$\huge\mathcal\blue{Corrected \: question:-}$

The area of a trapezium is 1512cm^2 . If the ratio of the parallel sides is 9:5 and the distance between them is 24 cm. Find the length of the parallel sides.

Given:-

The area of a trapezium is 15122 . If the ratio of the parallel sides is 9:5 and the distance between them is 24 cm.

To find:-

length of the parallel sides.

$\huge\mathfrak\green{Solution:-}$

Let the parallel sides be 9x and 5x

As we know area of trapezium=

$\frac{1}{2} \times a(base) + b(base) \times height$

or,

$\frac{a + b}{2} \times height$

Where a and b are base

By plugging the known values we get,

$\frac{9x + 5x}{2} \times 24cm = 1512 {cm}^{2}$

$\mapsto \: \frac{14x}{2} \times 24cm = 1512{cm}^{2}$

By cancelling with two we get,

$\mapsto \: \frac{14x}{1} \times 12cm = 1512 {cm}^{2}$

$\mapsto \: 14x = \frac{1512 {cm}^{2} }{24cm}$

$14x = 63cm$

$x = \frac{63}{14}$

$x = 4.5cm$

On substituting values with parallel sides we get,

9x=9(4.5cm) =40.5cm

5x=5(4.5cm) =22.5cm

Therefore the measure of parallel sides are 40.5cm and 22.5cm

Step-by-step explanation:

I hope it helps please mark me as brainliest