Question

the area of a trapezium is 165cm^2 and it’s height is 10cm. If one of the parallel side is double of the other, find the two parallel sides ​

Answer 1

Given :-

★ Area of trapezium = 165 cm²

★ Height of trapezium = 10 cm

★ One of the parallel side is double of the other.

To Find :-

★ Value of parallel sides

Solution :-

Let one side of trapezium be x

Therefore, the other side parallel to it = 2x

We know,

☞ Area of trapezium

= ½ ( Sum of parallel sides × Height)

Substituting the values, we get

Area of trapezium = ½ ( x +3x) 10

Now,

165 = ½ ( x +3x) 10

⟹ 165 = 3x ×5

⟹ x = 11

Hence,

The two parallel sides are 11 cm & 2x or 22 cm.

$\bold\blue{@ItzSilentColleen }$

Answer 2

Given ,

• Area of trapezium = 165 cm²
• Height of trapezium = 10 cm
• The one of the parallel side of trapezium is double of the other

Let ,

• The one side of trapezium be " x "
• Then , parallel side of x = 2x

We know that , the area of trapezium is given by

$\boxed{ \sf{Area = \frac{1}{2} ( Sum \: of \: parallel \: side \times Height )}}$

Thus ,

$\sf \mapsto 165 = \frac{1}{2} \{(x + 2x ) \times 10 \} \\ \\\sf \mapsto 165 = \frac{30x}{2} \\ \\\sf \mapsto x = \frac{165}{15} \\ \\\sf \mapsto x = 11$

$\sf \therefore {\underline{The \: parrallel \: sides \: of \: trapezium \: are \: 11 cm \: and \: 22 \: cm}}$