Question

The zeroes of the polynomial x2+7x+10 are:

-2, -5

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Answer 1

Answer:

x= -2, -5

Step-by-step explanation:

By splitting method...

=>x²+7x+10

=>10×1=10

=>10= 5×2

now, replacing 7x by 5x+2x

=>x²+5x+2x+10

=x(x+5)+2(x+5)

=(x+2)(x+5)

(i) x+2=0

x=0-2= -2

(ii) x+5=0

x=0-5= -5

Answer 2

Answer:

$p(x) = {x}^{2} + 7x + 10 \\ = > p( - 2)= { - 2}^{2} + 7( - 2) + 10 \\ = > - 4 + - 14 + 10 \\ = > - 8$

$p(x) = {x}^{2} + 7x + 10 \\ = > p( - 5)= { - 5}^{2} + 7( - 5) + 10 \\ = > - 25 + - 35 + 10 \\ = > - 50$

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