Question

The area of a trapezium is 168 cm sq and its height is 8cm. If one of the parallel sides is longer than the other by 6 cm, find the length of the other parallel sides .

Answer 1

1/2(sum of parallel sides)*h=area of parallel sides
1/2(x+6+x)*8=168
1/2*2x+6*8=168
x+48=168
x=168-48
x=120
x+6=120+6=126

Answer 2

$area \: of \: trapezium \: \\ = 1/2(sum \: of \: parallel \: sides) \times \\ \: height$

168=1/2*x+(X+6)*6
168/6=2x+6
28*2=2x+6
56-6=2x
x=50/2
x=25
first parallel sides=25cm
second parallel sides=x+6
=25+6
=31