Question

The area of a trapezium is 198 sq. cm and distance between its parallel sides is 12 cm.

The sum of the parallel sides is



(a) 32 cm
(b) 33 cm
(c) 36 cm
(d) 42 cm​

Answer 1

Answer:

Step-by-step explanation:

The area of a trapezium is 198 sq. cm and distance between its parallel sides is 12 cm. The sum of the parallel sides is (a) 32 cm (b) 33 cm (c) 36...

Answer 2

Given : The area of a trapezium is 198cm² and distance between it's parallel sides is 12cm.

To Find : Sum of the parallel sides.

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Here

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• Area of the trapezium = 198cm²
• Distance between it's parallel sides = 12cm

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As we know that :

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$\underline{\boxed{\sf\purple{\bigstar \: area \: of \: a \: trapezium \: = \frac{1}{2} \times sum \: of \: parallel \: sides \: \times distance \: between \: them \: }}}$

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Put the values in the formula and solve -

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$\sf:\implies \: \sf Area_{(trapezium)} = \dfrac{1}{2} \times sum \: of \: parallel \: sides \: \times distance \: between \: them \\ \\ \\ \sf:\implies \: Area_{(trapezium)} \frac{1}{2} \times sum \: of \: parallel \: sidesm \times 12 \\ \\ \\ \sf:\implies \: 198 = \frac{1}{\cancel{2}} \times sum \: of \: parallel \: sides \: \times \cancel12 \\ \\ \\ \sf:\implies \: \cancel\frac{198}{6} = sum \: of \: parallel \: sides \: \\ \\ \\ \sf:\implies \: sum \: of \: parallel \: sides \: = \underline{\boxed{\sf\purple{33cm}}}\bigstar \\ \\ \\ \sf\therefore{\underline{Hence, \: the \: sum \: of \: parallel \: sides \: of \: the \: trapezium \: is \: \bold{33cm}.}}$