Question

the area of a trapezium is 248 Sq. m and it's height is 8 m. If one of the parallel side is smaller than the other by 4m find the two parallel sides

Answer 1

Area of trapezium =248 sq.m
Height=8 m
Let one parallel side be x m
Therefore length of other parallel side =( x-4)m
According to the ques ,
Area of trapezium= 1/2(a+b)h
1/2(x+(x-4))8=248sq m
1/2(x+x-4)=248/8
(2x-4)=31×2
(2x-4)=62
2x =62+4
2x=66
X=66/2=33m
Two parallel sides =x=33m
=x-4=29 m
Mark as brainliest if it helped

Answer 2

Given:-

area of trapezium = 248 m square

height = 8 m

According to the question

one of the parallel side is smaller than the other by 4

Let (a) and (b) are two parallel sides

Let (a) = x

so,

(b) = x - 4

$\bf Area\:\: of\:\: trapezium = \frac{1}{2} \times (a + b) \times h \\ \\ = \frac{1}{2} \times (a + b) \times h = 248 \\ \\ = \frac{1}{2} \times (x + x - 4) \times 8 = 248 \\ \\ = (2x - 4 ) \times 4= 248 \\ \\ = (2x - 4 ) = \frac{248}{4} \\ \\ = (2x - 4) = 62 \\ = 2x = 62 + 4 \\ = 2x = 66 \\ \\ = x = \frac{66}{2} \\ \\ = x = 33$

so,

a = x = 33 m

b = x- 4 = 33 - 4 = 29 m

CHECK

AREA OF TRAPEZIUM

$\bf = \frac{1}{2} \times (a + b) \times h \\ \\ = \frac{1}{2} \times (33 + 29) \times 8 \\ \\ = 62 \times 4 \\ = 248 {m}^{2}$