Question

The area of a trapezium is 28cm2 and one of its parallel sides is 6 cm
If the distance between parallel sides is 4 cm , Then the other parallel
side is​

Answer 1

Answer:

8 CM

Step-by-step explanation:

area=1/2*4*(6+x)

28=1/2*4*(6+x)

56=24+4x

32=4x

x=8

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Answer 2

Given:-

• Area of the Trapezium is 28 cm².
• One of its parallel side is 6 cm.
• Distance between parallel sides is 4 cm.

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To find:-

• The other parallel side.

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Solution:-

Let,

• the other parallel side be x.

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★Formula used:-

${\dag}\:{\underline{\boxed{\sf{\purple{Area_{(trapezium)} = \dfrac{1}{2} \times sum\: of\: all\: parallel\: sides \times altitude}}}}}$

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$\tt\longmapsto{28 = \dfrac{1}{2} \times (6 + x) \times 4}$

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$\tt\longmapsto{28 = (6 + x) \times 2}$

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$\tt\longmapsto{\dfrac{28}{2} = 6 + x}$

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$\tt\longmapsto{14 = 6 + x}$

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$\tt\longmapsto{x = 14 - 6}$

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$\sf\longmapsto{\boxed{\red{x = 8\: cm}}}$

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Hence,

• the other parallel side is 8 cm.

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★More to know :-

$\sf{Area\;of\;Rectangle\;=\;Length\;\times\;Breadth}$

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$\sf{Area\;of\;Square\;=\;(Side)^{2}}$

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$\sf{Area\;of\;Triangle\;=\;\dfrac{1}{2}\;\times\;Base\;\times\;Height}$

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$\sf{Area\;of\;Parallelogram\;=\;Base\;\times\;Height}$

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$\sf{Area\;of\;Circle\;=\;\pi r^{2}}$

$\sf{Perimeter\;of\;Rectangle\;=\;2\;\times\;(Length\;+\;Breadth)}$

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$\sf{Perimeter\;of\;Rectangle\;=\;4\;\times\;(Side)}$

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$\sf{Perimeter\;of\;Circle\;=\;2\pi r}$