the area of a trapezium is 300m2.the perpendicular distance between the two parrellel sides is 15m . if the difference of the parrelel sids is 16m, find the length of parelel sides.
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Area of a trapezium A is given by
A = 1/2 (a + b) h
If one side is a, the other side is 'a-16' since the difference of the parallel sides is 16
⇒ 1/2 (a + a - 16) x 15 = 300
1/2 (2a - 16) x 15 = 300 Multiply both sides by 2
(2a - 16)x15 = 600 Divide both sides by 15
2a - 16 = 40
2a = 56
a = 28
28 - 16 = 12
∴ The sides are 28 m and 12 m
A = 1/2 (a + b) h
If one side is a, the other side is 'a-16' since the difference of the parallel sides is 16
⇒ 1/2 (a + a - 16) x 15 = 300
1/2 (2a - 16) x 15 = 300 Multiply both sides by 2
(2a - 16)x15 = 600 Divide both sides by 15
2a - 16 = 40
2a = 56
a = 28
28 - 16 = 12
∴ The sides are 28 m and 12 m
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