Question

The area of a trapezium is 34 cm2 and the length of one of the parallel sides is 10 cm and its height is 4 cm. Find the length of the other parallel sides.​

Answer 1

Given:

• area of the trapezium = 34cm²
• length of one side = 10cm
• height of the trapezium= 4cm

To Find:

length of the other parallel side of trapezium

Solution:

Let "b" be the length of other parallel side of trapezium

We Know That:

$\red { \boxed{ \sf{area \: of \: trapezium = \frac{1}{2} (a + b) \times h}}}$

therefore,

$\implies\tt \: 34 = \frac{1}{2} (10 + b) \times 4$

$\implies\tt \: 34 = (10 + b) \times 2$

$\implies\tt \: 34 = 20 + 2b$

$\implies\tt \: 34 \: - \: 20 = 2b$

$\implies\tt \: 14 = 2b$

$\implies\tt \: \frac{14}{2} = b$

$\implies \tt \underline \red {b \: = \: 7}$

Hence,

length of other side of trapezium is 7 cm

Answer 2

Given:

area of trapezium = 34cm^2

height = 4 cm

Let, x be the lenght of other parallel side

Solution:

Area of Trapezium = 1/2 (a+b) × 4

34 = 1/2 (10 + x) × 4

34 = (10 + x) × 2

34 = 20 + 2x

2x = 34 - 20

2x = 14

x = 14/2

x = 7

here is your ans hope it's help you.