Question

The area of a trapezium is 352 cm and the distance between its parallel sides is 16 cm. If one of the parallel sides is of length 25 cm, ſind the length of the other???​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

"

$\huge \boxed{ \sf \red{19cm}}$

Step-by-step explanation:

Given -

Trapezium's,

Area (a) = 352 cm²

Distance between parallel sides (h) = 16 cm

One of the parallel line (p) = 25 cm

.

To find -

The other parallel line (q)

.

Solution -

$\sf \: area \: of \: trapezium = \frac{(p + q)}{2} \times h \\ \\ = > \sf352 \: {cm}^{2} = \frac{(25cm + q)}{2} \times 16 \: cm \\ \\ = > \sf352 = \frac{16(25 + q)}{2} \\ \\ = > \sf352 = \frac{400 + 16q}{2} \\ \\ = > \sf352 \times 2 = 400 + 16q \\ \\ \sf = > 704 = 400 + 16q \\ \\ = > \sf704 - 400 = 16q \\ \\ = \sf > 304 = 16q \\ \\ \sf = > \frac{304}{16} = q \\ \\ \sf = > 19 = q \\ \\ \sf = > q = 19cm$

Hence other parallel side = 19 cm

hope it helps.