Question

The area of a trapezium is 36 cm and the
perpendicular distance between its parallel
sides is 6 cm. If the lengths of these parallel
sides are x cm and y cm, find the value of
(x + y). Given further that x is twice as big as
y, find the values of r and y.​

Answer 1

Answer:

Step-by-step explanation:

Working out:

In the question, area of a trapezium is given and also the Perpendicular distance/altitude is given. The sides are also given but in the form of variables.

We have to find the sum of parallel sides of the trapezium, Now we will wonder how can we do that because parallel sides are in given in variable form. It is because :

Area of trapezium = 1/2 × (Sum of parallel sides of the trapezium) × Perpendicular distance betwe ln the parallel sides..

Now let's plug the given values in the formula,

Area = 36 cm²

perpendicular distance = 6 cm

Sum of parallel sides = x + y

Putting in formula,

⇛ Area = 1/2 × Sum of || sides × altitude

⇛ 36 cm² = 1/2 × (x + y) × 6 cm

⇛ 36 cm² = 3 cm × (x + y)

Flipping it,

⇛ 3 cm × (x + y) = 36 cm²

⇛ x + y = 36 cm² / 3 cm

⇛ x + y = 12 cm

So, the value of x + y:

And we are done !!

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