The area of a trapezium is 540
.If the ratio of parallel sides is 7: 5 and
the distance between them is 18 ,find the length of parallel sides
Answers
Answered by
33
area of trapezium is =1/2×(a+b)×height
let both sides ratio is x then
1/2×(7x+5x)18=540
1/2×12x×18=540 then x=5and length is 35 and 25
let both sides ratio is x then
1/2×(7x+5x)18=540
1/2×12x×18=540 then x=5and length is 35 and 25
Answered by
85
Answer :
35 and 25
Step-by-step explanation :
Let the parallel sides of a trapezium be 7x and 5x respectively.
According to the question ;
Area of trapezium = 540
⇒ 1 / 2 × sum of || sides × height = 540
⇒ 1 / 2 × ( 7x + 5x ) × 18 = 540
⇒ 9 ( 12x ) = 540
⇒ 108 x = 540
⇒ x = 540/ 108
⇒ x = 5
Their parallel sides are ;
7x = 7 × 5 = 35
5x = 5 × 5 = 25
Hence, the length of parallel sides are 35 and 25.
35 and 25
Step-by-step explanation :
Let the parallel sides of a trapezium be 7x and 5x respectively.
According to the question ;
Area of trapezium = 540
⇒ 1 / 2 × sum of || sides × height = 540
⇒ 1 / 2 × ( 7x + 5x ) × 18 = 540
⇒ 9 ( 12x ) = 540
⇒ 108 x = 540
⇒ x = 540/ 108
⇒ x = 5
Their parallel sides are ;
7x = 7 × 5 = 35
5x = 5 × 5 = 25
Hence, the length of parallel sides are 35 and 25.
Liba25:
Thank you so much
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