Question

the area of a trapezium is 64 cm if, its parellel sides are 10cm and 6 cm, then find the distance between the parellel sides ​

Answer 1

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Given that,

➡ area of the trapezium is 64cm²

Using the formula :

Area of the trapezium = ½(a + b) h

=> 64 = ½ (10+6)h

=> 64 = ½ × 16h

=> 64 = 8h

=> h = 8 cm.

Hence, The distance between the parallel sides is 8cm.

Answer 2

Answer:

8 cm

Step-by-step explanation:

Given:

Area of trapezium = 64 cm².

First parallel side = 10 cm.

Second parallel side = 6 cm.

To find:

Distance between the parallel sides = ?

i.e. Height (h) = ?

Solution:

Area of trapezium = 1/2 × sum of parallel side × height

64 = 1/2 × (6 + 10) × h

64 × 2 = (6 + 10) × h

128 = 16h

128/16 = h

8 = h

i.e. h = 8cm

Therefore, distance between the parallel sides is 8cm.