Question

A sphete of deamrter 7.0 cm and mass 266.5 g float in a bath of liquid. As the temperature is raised, the sphere begins to sink at a temperature of 35^@ C. If the density of liqued is 1.527 g cm^(-3) at 0^@C, find the coeffiecient of cubical expamsion of the liquid. Neglect the expansion of the sphere.

Answer 1

Here is your answer:

Explanation:

At 0°C

ρo = 1.527 g/cm3

ρ35 = 266.5/ 4/3 π (3.5)3

ρ35 = 1.484 g/ cm3

so

ρ   1/V

ρθ/ ρo = Vo/ Vθ

ρθ/ ρo = 1/ 1+ λθ

ρθ (1+ λθ) = ρθ

(1+ λθ) = ρo/ ρθ

λθ =ρo - ρo/ ρθ

λ = (1.527 - 1.484)/ 1.484 x 35

   = 8.24 x 10 ^ -4