Math, asked by Anonymous, 6 months ago

The area of a trapezium of height 8m is 208 m.sq. sum of its parallel sides is ​

Answers

Answered by SajanJeevika
22

Given:

Area of trapezium= 248 m²

Height (h)= 8 m

Let the one parallel side be= x m

Other parallel side =( x-4) m

Area of trapezium = 1/2 ( sum of parallel sides) × height

248 = 1/2 ( X+ X- 4)× 8

248 = (2x - 4) × 4

248/4 = 2x-4

62 = 2x-4

62+4= 2x

66= 2x

X= 66/2

X= 33

One parallel side (X)= 33 m

Other parallel side(x-4)= 33-4= 29 m

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Answered by shalinimaggo18
0

Answer = 52m

Step-by-step explanation:

Area of trapezium given = 208m²

height given = 8m

parallel sides = ?

Area of trapezium = 1/2 × h ( parallel sides)

208. = 1/2 ×8 (parallel sides)

208×2/8. =( parallel sides)

52 m = (parallel sides )

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