Question

the area of a trapezium shaped field is 480m^2, the distance between two parallel sides is 15m and one of the parallel side is 20m . find the other parallel side.​

Answer 1

Given :

⬤ Area of Trapezium is 480 m².

⬤ Distance between two Parallel Sides is 15 m.

⬤ One Parallel Side is 20 m

To Find :

⬤ Other Parallel Side .

Formula Used :

$\sf[\:{Area\:of\: Trapezium=\dfrac{1}{2}\times{(Sum\:of\:Parallel\:Sides)}\times{h}\:]}$

Solution :

• One Parallel Side is 20 m

Let :

• Second Parallel Side be x .

Now :

According to the Formula :

480 = ½ × (Sum of Parallel Sides) × Height

480 = 1/2 × (20 + x) × 15

480 × 2 = (20 + x) × 15

960 = 30 + 15x

960 - 300 = 15x

660 = 15x

660/15 = x

44 = x

Therefore , Second Parallel Side is 44 m .

Answer 2

⠀⠀⠀⠀⠀⠀⠀${\huge{\underbrace{\rm{Question}}}}$

The area of a trapezium shaped field is 480m^2, the distance between two parallel sides is 15m and one of the parallel side is 20m . find the other parallel side.

⠀⠀⠀⠀⠀⠀⠀⠀${\huge{\underbrace{\rm{Answer}}}}$

Given:

• the area of a trapezium shaped field is 480 m²

• the distance between two parallel sides is 15 m

• one of the parallel side is 20m .

To find:

find the other parallel side.

Solution:

ABCD is a trapezium with parallel sides AB and CD

AB = 20 m and

Let the length of the other parallel side,CD be ' x ' m

• Area of the trapezium ( A ) = 480 m²

• Height of the trapezium ( h ) = 15 m

We know that ,

$\boxed{\bf{\pink{Area\:of\:trapezium=\dfrac{AB+CD}{2}×h}}}$

Where,

• AB + CD = sum of parallel sides

• h = height of the trapezium

ATQ,

$\sf{:\implies 480=\dfrac{20+x}{2}×15}$

$\sf{:\implies \dfrac{2×480}{15}=20+x}$

$\sf{:\implies 64=20+x}$

$\sf{:\implies 20+x=64}$

$\sf{:\implies x=64-20}$

$\sf{:\implies x=44}$

$\boxed{\bf{\red{x\:=\:CD\:=44}}}$

Hence,

${\pink{\underline{\underline{\purple{\textsf{\textbf{length\:of\:other\:parallel\:side\:is\:44\:m}}}}}}}$

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