Question

The area of a Trapezium Shaped Field is 480m² , the height is 15 cm and one of the parallel side is 20cm . Find the other side.​

Answer 1

$\large\underline{ \underline{ \sf \maltese\green{ \: Question:- }}}$

• The area of a Trapezium Shaped Field is 480m² , the height is 15 cm and one of the parallel side is 20cm . Find the other side.

$\large\underline{ \underline{ \sf \maltese\green{ \: Given:- }}}$

• Area of Trapezium = $\sf{480 {m}^{2} }$
• Height of Trapezium = $\sf{15m}$
• One of the Parallel Side of Trapezium = $\sf{20m}$

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$\large\underline{ \underline{ \sf \maltese\green{ \: Solution:- }}}$

$\begin{gathered}\begin{gathered}\begin{gathered}: \implies \underline\blue{ \boxed{\displaystyle \sf \bold\orange{\:Area_{(Trapezium)\: = \: \frac{1}{2} \: \times \: (Sum \: of \: Parllel \: Sides) \: \times \:Height }}}}\\ \\\end{gathered}\end{gathered}\end{gathered}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ 480 \: = \: \frac{1}{2} \: \times \: (AB \:+ \:CD) \: \times \: AL }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ 480 \: = \: \frac{1}{2} \: \times \: (20 \:+ \:CD) \: \times \: 15 }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ \frac{480 \: \times \: 2}{15} \: = \: 20 \:+ \:CD\: }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ \frac{\cancel{480} \: \times \: 2}{\cancel{15}} \: = \: 20 \:+ \:CD\: }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ 32 \: \times \: 2 \: = \: 20 \:+ \:CD\: }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ 64\: = \: 20 \:+ \:CD\: }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ 64\:- \: 20 \: = \:CD\: }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ 44\: = \:CD\: }}$

$\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{CD \: = \: 44cm }}}$

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$\begin{gathered}\begin{gathered}\therefore\: \sf{ The \: other \: side \: of \: the \: Trapezium \: = \underline {\underline{ 44cm}}}\\\end{gathered}\end{gathered}$

Note:-

• Diagram is in the attachment

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