Question

the area of a Trapezium whose length of a parallel sides are 12cm and 16cm and distance between them is 4cm is_sq.cm​

Answer 1

Answer:

Step-by-step explanation:

Given: Base of trapezium (b  

1

​  

)=16 dm

Base of trapezium (b  

2

​  

)=22 dm

Height of trapezium (h)=12 dm

Now, Area of trapezium =  

2

1

​  

×(b  

1

​  

+b  

2

​  

)×h

                                        =  

2

1

​  

×(16+22)×12

                                        =  

2

1

​  

×38×12

                                        =228 dm  

2

 

                                        =  

100

228

​  

 m  

2

[∵1 dm  

2

=  

100

1

​  

 m  

2

]

                                        =2.28 m  

2

Answer 2

Answer:

56 sq cm

Step-by-step explanation:

1/2(a+b)h

1/2(12+16)4

1/2(28)4

14×4

=56 sq cm