Math, asked by rajsadhwani61203, 7 months ago


The area of a trapezium with height 3.2 cm and sum of its parallel sides
as 60 cm will be​

Answers

Answered by zoya12515
1

Step-by-step explanation:

Area oftrapezium=[(1/2) (height) (sum of its

parallell sides)]

=[(1/2)(3.2cm)(60cm)]

=32×3cm^2

=96cm^2

Answered by santoshthalla143
0

Answer:

Given that,

Some points to us

Step-by-step explanation:

Area of trapezium is

=1/2(a+b)h

Height =3.2cm

A+B=60 cm

A=60-B

Area of trapezium is 1/2(a+b)h

=1/2((60-b)+B)3.2

=1/2(60)3.2

=30*3.2

=105

Area of trapezium is =105 sq. Cm

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