The area of a triangle is 108 cm2. If the respective ratio between height and base is 3:2, what is the perimeter of a square whose side is equal to twice the base of the triangle ?(in cm)
Answers
Question :-- The area of a triangle is 108 cm2. If the respective ratio between height and base is 3:2, what is the perimeter of a square whose side is equal to twice the base of the triangle ?(in cm)
Formula used :--
→ Area of ∆ = 1/2 * Base * Height .
→ Area of Square = 4 * side .
Solution :--
Let Base of ∆ = 2x .
Height of ∆ = 3x.
→ Area of ∆ = 1/2 * 2x * 3x = 3x².
Given, Area of ∆ = 108cm².
so, putting both Equal we get,
→ 3x² = 108
→ x² = 36
→ x = 6 .
So, Base of ∆ = 2x = 2*6 = 12cm. .
Now, it is given that , side of square is Twice base of ∆.
So,
→ side of Square = 2*12 = 24cm.
→ Perimeter of square = 4*24 = 96cm.
Hence, perimeter of Square whose side is Twice base of ∆ is 96cm..
Answer:
Step-by-step explanation:
Given that:-
Let the base of triangle = 2x and the height of triangle = 3x .
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Dimensions:-
Base of triangle = 2x =(2 × 6) = 12 cm
Height of triangle =3x=(3 × 6) = 18 cm