Question

The area of a triangle is 2x square+4x and its base is x+2. Find its altitude.

Answer 1

Step-by-step explanation:

Given :-

The area of a triangle is 2x square+4x and its base is x+2.

To find:-

Find its altitude ?

Solution:-

Given that :

Base of a triangle = (x+2) units

Let the altitude of the triangle be h units

Area of a triangle = (1/2) bh sq.units

=> (1/2)(x+2)h sq.units

=>[(x+2)h]/2 sq.unirs

According to the given problem

Area of the triangle = 2x^2+4x

=> [(x+2)h]/2 = 2x^2+4x

=> (x+2)h = (2x^2+4x)×2

=> (x+2)h = 4x^2+8x

=> h = (4x^2+8x)/(x+2)

=> h = 4x(x+2)/(x+2)

=> h = 4x units

Answer:-

The altitude of the given triangle is 4x units

Check:-

Base = (x+2)

altitude= 4x

Area of the triangle

=> (1/2)bh

=> (1/2)(x+2)(4x)

=> (x+2)(2x)

=> 2x^2+4x

Verified the given relations in the problem.

Used formulae:-

• Area of a triangle = (1/2) bh sq.units

Where, b = base

h = height or altitude

Answer 2

Step-by-step explanation:

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