Question

The area of a triangle is 50 cm2 . if the altitude is of 8 cm , what is the length of its base ?

Answer 1

Let base be b.

1/2*b*h=50cm^2

=1/2*b*8cm=50cm^2

b=50/4cm^2

b=12.5cm

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Answer 2

The base of length of a triangle(b) is 12.5 cm.

Step-by-step explanation:

We have,

The area of a triangle = 50 $cm^2$ and  the altitude of a triangle(h) = 8 cm

To find, the base of length of a triangle(b) = ?

We know that,

The area of a triangle = $\dfrac{1}{2}$ × b × h

⇒ $\dfrac{1}{2}$ × b × 8 = 50

⇒ b × 4 = 50

⇒ $b=\frac{50}{4} cm$

⇒ b = 12.5 cm

∴ The base of length of a triangle(b) = 12.5 cm

Hence, the base of length of a triangle(b) is 12.5 cm.