Question

The area of a triangle is 6 sq.cm.If its base is 5 cm,then its height is​

Answer 1

Answer:

HERE,THE AREA OF RIGHT ANGLED TRIANGLE IS ALSO GIVEN.

WITHOUT THE AREA ALSO IT MAY WORKED BY PYTHAGORAS THEOREM.

AREA OF TRIANGLE=1/2×b×h

6=1/2×4×h

6=2h

h=6/2

h=3cm

we have,

base=4cm

height=3cm

Hypotenuse=5cm

PERIMETER OF RIGHT ANGLED TRIANGLE =base+height +hypotenuse

=4+3+5

=12cm.

thus the perimeter of the right angled triangle is 12cm

PLZ MARK AS BRIANLIEST,FLW ME AND THX FOR THE SUPERB QUESTION

Answer 2

Answer:

$➟ Area of ∆ = 15 cm²</p><p></p><p>➟ Height of ∆ = 6 cm$

$</p><p>\:\:\:\: \Large \underline {\sf{To\:Find\::}} </p><p>ToFind:</p><p>$

$➟ Base of ∆$

$\:\:\:\: \Large \underline {\sf{Solution\::}} </p><p>Solution:</p><p>$

$➟ Let the base be " b "</p><p> </p><p> ×base×height$

$\begin{gathered}\underline{\boxed{\sf{\red{Formula\:used\:=\: \dfrac{1}{2} \times base \times height}}}} \\ \\ \end{gathered} </p><p>Formulaused= </p><p>2</p><p>1$

$\begin{gathered}\implies \sf 15\:=\: \dfrac{1}{2} \times b \times 6 \\ \\ \end{gathered} </p><p>⟹15= </p><p>2</p><p>1$

$\begin{gathered}\implies \sf 6b\:=\: 15 \times 2 \\ \\ \end{gathered} </p><p>⟹6b=15×2</p><p> ×b×6$

$</p><p>\begin{gathered}\implies \sf 6b\:=\: 30 \\ \\ \end{gathered} </p><p>⟹6b=30$

$\begin{gathered}\implies \sf b\:=\: \cancel \dfrac{30}{6} \\ \\ \\ \end{gathered} </p><p>⟹b= </p><p>6</p><p>30</p><p> </p><p> </p><p> </p><p> </p><p>$

$\begin{gathered}\:\:\:\:\:\:\: \Large {\underline{\underline{\sf{Base\:=\:5\:cm}}}} \\ \\ \\ \end{gathered}$

$Final ans is 5 cm</p><p>And we are done !$

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