The area of a triangle is 600sq. cm. and its altitude is 80cm., then its base is
Answers
Answered by
0
Answer:
Given base of triangle exceeds altitude by 10 cm
Let the altitude be x cm
Therefore, base =(x+10) cm
Area of triangle =
2
1
× base × altitude
⇒600=
2
1
×(x+10)×x
⇒1200=x
2
+10x
⇒x
2
+10x−1200=0
⇒x
2
+40x−30x−1200=0
⇒x(x+40)−30(x+40)=0
⇒(x+40)(x−30)=0
∴x=−40,x=30
But x cannot be negative.
Hence, x=30cm
That is altitude=30cm
∴ Base=40cm
Answered by
1
Answer:
15
Step-by-step explanation:
Area of triangle= 1/2 *b *h
600=1/2*80*b
1200=80*b
b=1200/80
b = 15
base =15 cm
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