Question

The area of a triangle is 90 cm .if its base is 20 cm long find the mearsure of its corresponding altitude​

Answer 1

90=1/2*20*altitude

altitude=90/10

=9 cm

Answer 2

$\large\sf\underline{Correct\:Question\::}$

• The area of a triangle is 90 sq. cm . If its base is 20 cm long , find the measure of its corresponding altitude ( height ) .

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$\large\sf\underline{Given\::}$

• Area of triangle = 90 sq.cm.

• Base of triangle = 20 cm.

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$\large\sf\underline{To\:find\::}$

• Height or altitude of the triangle.

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$\large\sf\underline{Solution\::}$

We know ,

★ $\small{\underline{\boxed{\mathrm\pink{Area\:of\:∆\:=\:\frac{1}{2} \times base \times height}}}}$

• Let's substitute the given values in the formula

$\sf\implies\:90\:=\:\frac{1}{2} \times 20 \times h$

$\sf\implies\:90\:=\:\frac{20}{2} \times h$

$\sf\implies\:90\:=\:\frac{20h}{2}$

• Cross multiplying

$\sf\implies\:20h\:=\:90 \times 2$

$\sf\implies\:20h\:=\:180$

• Transposing 20 to the other side

$\sf\implies\:h\:=\:\frac{18\cancel{0}}{2\cancel{0}}$

$\sf\implies\:h\:=\:\cancel{\frac{18}{2}}$

$\large{\mathfrak\red{\implies\:h\:=\:9\:cm}}$

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‎ $\dag\:\underline{\sf So\:altitude\:of\:∆\:is\:9\:cm.}$

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!! Hope it helps !!