Question

The area of a triangle is equal to that of a square whose each side measures 70 cm find the side of the triangle in metres corresponding to the altitude measuring 35 cm

Answer 1

$\huge\mathbb{\red{SOLUTION:-}}$

• Given that the area if square=area of triangle

$\bold{Given}\begin{cases}\sf{Side\:of\: square=70cm}\\ \sf{Altitude\:of\: triangle=35cm}\end{cases}$

• We have to find the side of triangle

$\bf\underline{According\:to\: Question:-}$

• Let find the area of square

$\boxed{\sf{Area\:of\:square=side\times side}}$

$\sf Area=70\times 70\\ \sf\implies 4900cm{}^{2}$

• So the area if square is
• $\sf\implies 4900cm{}^{2}$

• Then the. area if triangle is also
• $\sf\implies 4900cm{}^{2}$

Now we have to find the base of triangle

$\boxed{\sf{Area\:of\: traingle=\frac{1}{2}\times base\times height}}$

$\sf 4900=\frac{1}{2}\times base\times 35\\ \\ \sf\implies 4900\times 2=base\times 35 \\ \\\sf\implies 9800=base\times 35\\ \\ \sf\implies \cancel{\frac{9800}{35}}=base\\ \\ \sf\implies base=280cm$

$\boxed{\sf{Base=280cm}}$

#BAL

#answerwithquality

Answer 2

$\underline \mathbb{SOLUTION}$

IT IS GIVEN THAT , AREA OF Square = AREA OF 35 cm.

$\underline \mathbb{TO\:FIND}$

》SIDE OF TRIANGLE

$\underline \mathbb{ATQ}$

$\underline \mathbb{LET}$

Find the area of square

$= > area = side \times side$

$= > area = 70 \times 70 = 4900 {cm}^{2}$

THEREFORE, AREA OF TRIANGLE = AREA OF SQUARE

$= > 4900 {cm}^{2}$

$\underline \mathbb{NOW}$

》WE HAVE TO FIND THE BASE OF TRIANGLE.

$area \: of \: triangle= \frac{1}{2} \times base \: \times height$

$= > 4900 = \frac{1}{2} \times base \times 35$

$= > 4900 \times 2 = base \times 35$

$= > 9800 = base \times 35$

$= > Base =\frac{9800}{35}$

$= > base = 280cm$

$\underline \mathbb{ANSWER= 280 cm}$

_______________________________________

#BAL

#Answerwithquality