Question

the area of a triangle whose sides are 4cm, 13cm, 15cm​

Answer 1

S= 4+13+15/2 = 16
Ar of triangle = under root 16(16-4)(16-13)(16-15)
= under root 16(12)(3)(1)
=under root 2X2X2X2X2X2X3X3X1
= 24 cm sq

Answer 2

Given:

The three sides of a triangle are 4cm, 13cm and 15cm.

To find:

The area of a triangle.

Solution:

The area of a triangle is 24 square centimetres.

To answer this question, we will follow the following steps:

As given, we have,

The three sides of a triangle = 4cm, 13cm and 15cm

Now,

The area of a triangle is given by using Heron's formula which is

$\sqrt{s(s - a) (s - b)(s - c)}$

where 's' is equal to the half of the perimeter of the triangle and a, b and c are three sides of a triangle.

So,

The perimeter of the given triangle

= sum of lengths of all three sides

$= 4 + 13 + 15$

$= 32 \: cm$

Half of perimeter = 32/2 = 16 cm

So,

Area of the given triangle

$= \sqrt{16(16 - 4) (16 - 13)(16 - 15)}$

$= \sqrt{16(12)(3)(1)}$

$= \sqrt{576 \: }$

$= 24 \: {cm}^{2}$

Hence, the area of a given triangle is 24 square centimetres.