Question

The area of a triangle with vertices (1, -3).
(4, k) and (-9, 7) is 15 square units. Find
the value/s of k.​

Answer 1

Step-by-step explanation:

in coordinate geometry we use the formula

area = 1/2 | x1 (y2 - y3) + x2 (y3 - y1) + x3 (y1 - y2) |

$15= \frac{1}{2} |1(k - 7) + 4(7 - ( - 3)) + ( - 9)( - 3 - k)| \\ 15 = \frac{1}{2} |k - 7 + 4(10) + 27 + 9k| \\ 15 = \frac{1}{2} |k - 7 + 40 + 27 + 9k| \\ 15 = \frac{1}{2} |10k + 60| \\ 15 \times 2 = 10k + 60 \\ 30 = 10k + 60 \\ 10k = 30 - 60 \\ 10k = - 30 \\ k = \frac{ - 30}{10} \\ k = - 3$

k = -3

hope you get your answer

Answer 2

Answer:

k = -3 / k = -9

hope its helpful