The area of a triangle with vertices A (0, 8), O (0, 0), and B (5, 0)
Answers
Answered by
0
Answer:
20
Step-by-step explanation:
area of triangle = 1/2I0(0-0)+0(0-8)+5(8-0)I
= 1/2 I 0+0+40I
=1/2X40
= 20 Sq.units
Answered by
1
20 sq units
The area formula of AOB is
1/2[|x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|]
So by putting the values I get this..
Note that x1 and x2 are 0
AND X3 is 5
So area=1/2[|5(8-0)|]
This gives area as 20
***Note-'||'This symbol denotes mod as area is always position
PLEASE UPVOTE AND MARK BRAINLIEST AS IT TAKES HARDWORK TO WRITE THE ANSWER
Similar questions