Math, asked by lariya13862, 11 months ago

The area of a triangle with vertices A (0, 8), O (0, 0), and B (5, 0)

Answers

Answered by suriya2002
0

Answer:

20

Step-by-step explanation:

area of triangle = 1/2I0(0-0)+0(0-8)+5(8-0)I

                            = 1/2 I 0+0+40I

                            =1/2X40

                           = 20 Sq.units

Answered by buchi
1

20 sq units

The area formula of AOB is

1/2[|x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|]

So by putting the values I get this..

Note that x1 and x2 are 0

AND X3 is 5

So area=1/2[|5(8-0)|]

This gives area as 20

***Note-'||'This symbol denotes mod as area is always position

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