Math, asked by Nurenmemon, 16 days ago

The area of a triangle with vertices a (3, 0), (7, 0) and (9, 2) is ____ square unit​

Answers

Answered by prakashcor
0

Answer:The area of the  ΔABC with vertices  

A(x  

1

​  

,y  

1

​  

)=(3,0),B(x  

2

​  

,y  

2

​  

)=(7,0) & C(x  

3

​  

,y  

3

​  

)=(8,4) is  

Ar.ΔABC=  

2

1

​  

[x  

1

​  

(y  

2

​  

−y  

3

​  

)+x  

2

​  

(y  

3

​  

−y  

1

​  

)+x  

3

​  

(y  

1

​  

−y  

2

​  

)]

=  

2

1

​  

{3(0−4)+7(4−0)+8(0−0)} sq.units =8 sq. units.

Step-by-step explanation:

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