The area of a triangle with vertices a (3, 0), (7, 0) and (9, 2) is ____ square unit
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Answer:The area of the ΔABC with vertices
A(x
1
,y
1
)=(3,0),B(x
2
,y
2
)=(7,0) & C(x
3
,y
3
)=(8,4) is
Ar.ΔABC=
2
1
[x
1
(y
2
−y
3
)+x
2
(y
3
−y
1
)+x
3
(y
1
−y
2
)]
=
2
1
{3(0−4)+7(4−0)+8(0−0)} sq.units =8 sq. units.
Step-by-step explanation:
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