Question

the area of a triangle with vertices at (-3,-2), (3.-2), and (1,2) is

Answer 1

Answer:

The area of triangle = 1/2[x1(y2-y3) + x2(y3-y1) + x3(y1-y2)]

therefore , vertices are (-3,-2),(3,-2)(1,2)

so, x1= -3, y1 = -2;

x2 = 3, y2 = -2;

x3 = 1, y3 = 2;

area = 1/2[(-3)(-2-2) + (3)(2+2) + 1(-2+2)

       = 1/2[(-3)(-4) + (3)(4) + (1)(0)]

       = 1/2[12 + 12]

area = 1/2[24]

area = 12 ....Ans

Answer 2

Answer:

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