The area of AABC having vertices A(1,-1), B(-4, 6) and C(-3,-5) is.........
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Step-by-step explanation:
area of triangle=1/2(x1(y2-y3) +x2(y3-y1) +x3(y1-y2)
=1/2[1(11)+(-4)-4)+(-3)-7
=1/2[11+16-21]
1/2[6]
=3squnits
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