Question

the area of ∆ABC is 108cm² and its height AD=12cm, find BC.​

Answer 1

Answer:

18 CM^2

Step-by-step explanation:

AREA OF TRIANGLE=

$\frac{1}{2} \base \ height$

$given \: area \: of \: triangle = 108cm ^{2}$

$= 108cm^{2} =\frac{1}{2} \bc \da$

$= 108 cm^{2} =\frac{1}{2} bc \times 12 = bc = 6$

$= \frac{108}{6} = bc = 18$

HENCE YOUR ANSWER IS 18..