Question

the area of an equilateral triangle is 49
$\sqrt{3cm \:} \: square$
taking each angular point as centre a circle is described with radius equal to half the length of the side of the triangle as shown in figure find the area of the portion in the triangle not included in the circles

plzz answer​

Answer 1

Step-by-step explanation:

this is the answer with explanation

Answer 2

Hey mate here is your answer ❤️

Area = 1/2 a×a sin 60°=49✓3

a²=2 ×49✓3 / sin 60°

= 196

a = 14cm

Half of the side = 7cm = radius of circle

Area of inclined in circle

=3×22/7×7² × 60/360

=77cm²

Area inclined

= 49✓3-77

=7.87cm²

Hope it will help you ☺️☺️