Question

the area of an equilateral triangle is 9✓3cm² the length of its side is​

Answer 1

Given :-

area of an equilateral triangle = 9√3 cm²

To find :-

The side of equilateral triangle having area 9√3 cm².

Formula :-

$Area \: of \: equilateral \: triangle = \frac{\sqrt{3} }{4} a^{2}$

Solution :-

$9 \sqrt{3} \: {cm}^{2} = \frac{ \sqrt{3} }{4} s^{2} \\ \\ = > {s}^{2} = \frac{9 \sqrt{3} \: {cm}^{2} \times 4}{ \sqrt{3} } \\ \\ = > {s}^{2} =9 \: {cm}^{2} \times 4 \\ \\ = > {s}^{2} =36 \: {cm}^{2} \\ \\ = > s = \sqrt{36 {cm}^{2} } \\ \\ = > s \: = 6 \: cm$

Answer :-

The side is 6cm.