Question

the area of an equiletral triangle ,whose heigh 8dm is__________dm2​

Answer 1

SOLUTION :

• Area of equilateral triangle = √3(a²)/4
• Where a is side of triangle.
• General area of triangle = 1/2*(base).(height)

• Let the side of eqilateral triangle is a
• Then bisected sides are a/2
• Height = 8 dm

• In Δ ABH
• a² = a²/2² + 8²
• a² - a²/4 = 64
• 3a²/4 = 64
• a² = 64×4/3
• a² = 256/3

• Area of equilateral triangle = √3(a²)/4
• Area of equilateral triangle = √3(256)/4×3
• Area of equilateral triangle = (64)/√3
• Area of equilateral triangle = 64√3 /3 dm²