the area of an isosceles tangle whose perimeter is 30cm and each of the equal sides is 12cm is
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Answered by
2
Semiperimeter (s) = 30/2 = 15
three sides are respectively: 12cm, 12cm and 30-24=6cm
area = sqrt[s(s-a)(s-b)(s-c)]
= sqrt[ 15(15-12)(15-12)(15-6)]
= sqrt[ 15*3*3*9]
= 9 sqrt(15) cm^2
three sides are respectively: 12cm, 12cm and 30-24=6cm
area = sqrt[s(s-a)(s-b)(s-c)]
= sqrt[ 15(15-12)(15-12)(15-6)]
= sqrt[ 15*3*3*9]
= 9 sqrt(15) cm^2
Answered by
0
Perimeter=30cm
Third side is 30-24=6
Area=√[s(s-a)(s-b)(s-c)]
a=12,b=12,c=6
S=(12+12+6)/2=15
Area=√{15*3*3*9]=√1215=34.8
Third side is 30-24=6
Area=√[s(s-a)(s-b)(s-c)]
a=12,b=12,c=6
S=(12+12+6)/2=15
Area=√{15*3*3*9]=√1215=34.8
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