Question

The area of an isosceles triangle having base 4 cm and the lengths of one of the equal sides 5 cm is *​

Answer 1

Answer:

a=4

b=5

c=5

According to heron's formula,

=4+5+5/2

=14/2

=7

=$\sqrt{s(s-a)(s-b)(s-c)}$

=$\sqrt{7*4*5*5}$

=$\sqrt{7*2*2*5*5}$

=$5*2\sqrt{7}$

=$10\sqrt{7$ cm2

Brainliest please....