Question

the area of an isosceles triangle is 12 CM square if one of its equal side is 5 cm find its base​

Answer 1

Answer:

Step-by-step explanation:

Let the base be b cms.

Then the semi-perimeter s = (b+5+5)/2 = (b+10)/2.

By Heron's formula, area of the triangle = rt {s(s-a)(s-b)(s-c)}

i.e., 12 = rt{(b+10)/2 ((b+10)/2 -b))((b+10)/2 -5)((b+10)/2 -5))

Squaring, 144 = (b+10)/2 (10-b)/2 (b/2)(b/2)

Simplifying we get b^4 -100b^2 + 2304 = 0 which yields b = 6 or 8.

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